factorise the following by using a suitable identity : a ) 2a raise to5 - 54a raise to 2
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Answered by
18
2a⁵ - 54a² = 2a²(a³ -27) = 2a² (a-3)(a² + 3² +3a) = 2a² (a-3)(a² + 9 + 3a)
Answered by
49
2a^5- 54 a²
=2 a²( a³- 27 )
= 2 a² [ a³-3³ ]
We know that,
x³ - y³= ( x - y ) ( x²+ xy + y² )
= 2 a² ×( a - 3 ) ( a²+3a+3² )
=2a²(a-3)(a²+3a+9)
Hope it helps...
=2 a²( a³- 27 )
= 2 a² [ a³-3³ ]
We know that,
x³ - y³= ( x - y ) ( x²+ xy + y² )
= 2 a² ×( a - 3 ) ( a²+3a+3² )
=2a²(a-3)(a²+3a+9)
Hope it helps...
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