factorise the following equation p4+q4+p2q2
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Answered by
98
p4+q4+p2q2
=p4+q4+2(p2q2)-p2q2
=(p2+q2)2 -(p2q2)2
=(p2+q2)2-(pq)2
=(p2+q2+pq)(p2+q2-pq)
=p4+q4+2(p2q2)-p2q2
=(p2+q2)2 -(p2q2)2
=(p2+q2)2-(pq)2
=(p2+q2+pq)(p2+q2-pq)
Answered by
45
p4+q4+p2q2
p4+q4+2(p2q2)-p2q2
(p2+q2)2 -(p2q2)2
(p2+q2)2-(pq)2
(p2+q2+pq)(p2+q2-pq)
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