Question

factorise the following expression by using the concept of HCF of term. 54ab³ - 81bc² + 27a²c³​

Answer 1

Answer:

27(2ab^3 - 3bc^2 + a^2c^3)

Step-by-step explanation:

HCF of coefficients:

HCF(54,81,27) = 27. Thus 27 will be the coefficient of the answer.

HCF of variables:

HCf(ab^3,bc^2,a^2c^3)

The most we can factorise from these while keeping them polynomials is -

ab^3 - bc^2 + a^2c^3. There is no common term other than 1.

Answer - 27(2ab^3 - 3bc^2 + a^2c^3)

[54 = 27*2]

[-81 = 27*-3]

[27 = 27*1]