Question

what is the derivative of sinx w. r. t cotx​

Answer 1

Answer:

dv/du = -cotx

Step-by-step explanation:

Let u = sinx. and v = cosx

So, we need to find dv/du

On differentiating w.r. t. 'x', we get

dx/du = dx/d (sinx) = cosx and 

dx/dv = dx/d (cosx) = −sinx

∴ dv/du = −sinx / cosx = −cotx