Question

factorise the following expression using identities. -x^2-6x-9
​

Answer 1

-x²-6x-9

...............

3*3=9

3+3=6

.....

-x²-(3x+3x)-9

= -x²-3x-3x-9

=-x(x-3)-3(x-3)

=x-3(x-3)...but here you can se -(-) =(+) so....

ans= x-3(x+3) ans