Question

Factorise the following expressions :
(i) p^3+27​

Answer 1

${p}^{3} + 27$

Rewrite 27 as 33 . Since both terms are perfect cubes, factor using the sum of cubes formula, a3+b3=(a+b)(a2−ab+b2) a 3 + b 3 = ( a + b ) ( a 2 - a b + b 2 ) where a=p. and b=3 . Simplify.

Answer 2

Answer:

Answer:(p+3)(p^2-pq+3^2)

Answer:(p+3)(p^2-pq+3^2) hope it helps you

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