factorise the following polynomial:- (a²+1/a²)-10(a+1/a)+27
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Answer:
{3,4,5,6,7,8} = {x ∈ Z : 3 ≤ x ≤ 8} = {x ∈ N : 3 ≤ x ≤ 8} ... 13. R3 ⊆ R3 is true because any set is a subset of itself. 15. {(x, y) : x−1 ... Plugging d = 2e back into 2a = 7d gives 2a = 14e.
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Step-by-step explanation:
(a+1/a)(a+1/a-10+27)
(a+1/a)(a+1/a+17)
keep going
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