Question

Factorise the following polynomial
I) ( x^2 - x) - 8 ( x^2 - x) + 12.

fast answer I need it.

Answer 1

N1⋅N2=a⋅c=1⋅12=12
AND
N1+N2=b=−8

After trying out a few numbers we get N1=−2 and N2=−6
−2⋅−6=12 and −2−6=−8

x2−8x+12=x2−6x−2x+12

=x(x−6)−2(x−6)

(x−2)(x−6) is the factorised form of the 

Answer 2

Hello friend
-----------------

Thanks for the question.

=) In example

(x^2 - x )^2 - 8 ( x^2 - x) + 12 = ?

therefore x^2 - x = m taking.

=) (m)^2 - 8 (m) + (12)

=) m^2 - 8m + 12

=) m^2 - 6m - 2m + 12

=) m(m - 6) -2 ( m - 6 )

=) ( m - 6 ) ( m - 2 )

Now substitute the value of m with x^2 - x

=) ( x^2 - x - 6 ) ( x^2 - x - 3 )

=) [ ( x^2 - 3x + 2x - 6) ]. [(x^2 - 2x + x - 2)]
-----------. ---------. -----------. -------
=) [x( x -3 ) + 2( x - 3 )] [x( x - 2) + 1(x - 2)]

=) ( x - 3 ) ( x + 2 ) ( x - 2 ) ( x + 1 )

This is the answer..⏫⏫⏫⏫.

I hope this will helps you.

keep asking.

Thanks.