Question

factorise the following
$(2a + 3b)^{3} - 27c ^{3}$
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Answer 1

$(2a+3b)^{3}-27c^{3} =(2a+3b-3c)((2a+3b)^{2}+9c^{2}+(2a+3b)(3c)) =(2a+3b-3c)(4a^{2}+9b^{2}+9c^{2}+12ab+6ac+9bc)$

Answer 2

Step-by-step explanation:

pls refer to the attachment