Question

factorise the following trinomial 1) a^2+19a-20
2) x^2-14x+24...​

Answer 1

Step-by-step explanation:

Correct option is

A

(x−2)(x−12)

In the given polynomial x

2

−14x+24,

The first term is x

2

and its coefficient is 1.

The middle term is −14x and its coefficient is −14.

The last term is a constant term 24.

Multiply the coefficient of the first term by the constant 1×24=24.

We now find the factor of 24 whose sum equals the coefficient of the middle term, which is −14 and then factorize the polynomial x

2

−14x+24 as shown below:

x

2

−14x+24

=x

2

−12x−2x+24

=x(x−12)−2(x−12)

=(x−2)(x−12)

Hence, x

2

−14x+24=(x−2)(x−12

Answer 2

Answer:

this answer is right