factorise the following using appropriate identities x²-y²by100
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x²-y²/100
= x²/100 - y²/100
= (x/10)² - (y/10)²
= ( x /10 + y/10) ( x/10 - y/10)
= (x+y/10) ( x-y/10)
Hope helped!
= x²/100 - y²/100
= (x/10)² - (y/10)²
= ( x /10 + y/10) ( x/10 - y/10)
= (x+y/10) ( x-y/10)
Hope helped!
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