Factorise the following using suitable identities: 4 (i) 49a 2 +25b 2 +70ab
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Answer:
We know 49a
2
+70ab+25b
2
=(7a)
2
+2(7a)(5b)+(5b)
2
We know that x
2
+2xy+y
2
=(x+y)
Here x=7a and y=5b
Therefore, 49a
2
+70ab+25b
2
=(7a)
2
+2(7a)(5b)+(5b)
2
=(7a+5b)
2
=(7a+5b)(7a+5b)
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