Question

In sulphur estimation, 0.2 g of an organic compound gave 0.466 g of barium sulphate. The percentage of sulphur in the compound is ??(Molecular mass BaSO4 = 233 u)​

Answer 1

Explanation:

Mass of Organic Substance = 0.234 g

Mass of Barium Sulphate = 0.334 g

Molecular Mass of BaSO  

4

​

 = 233 gmol  

−1

 

233 g of BaSO  

4

​

 contain 32 g of Sulphur

0.334 g of barium sulphate would contain  

233

32

​

×0.334 = 0.0458 g

% of Sulphur =  

0.234

0.0458

​

×100 = 19.6%