Factorise the following : x^6-1
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Answered by
1
Answer:
There are two methods for the same.
Step-by-step explanation:
a)
x^6 - 1
= (x^3)^2 - 1
= (x^3 + 1)(x^3 - 1)
= (x+1)(x^2 - x + 1)(x-1)(x^2 + x +1)
= (x+1)(x-1)(x^2 - x +1)(x^2 + x + 1)
b)
x^6 - 1
= (x^2)^3 - 1
= (x^2 - 1)(x^4 + x^2 + 1)
= (x+1)(x-1)(x^4+2x^2+1 - x^2)
= (x+1)(x-1)[(x^2+1)^2 - x^2)
= (x+1)(x-1)(x^2-x+1)(x^2+x+1)
Answered by
1
(X^3)2-(1)^2
(X^3+1) (X^3-1)
(X+1) (X2-X+1) (X-1) (X^2+X+1)
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