Question

Factorise the following :x3+8y3+6xy-1x cube + 8 y cube + 6 x y - 1 ​

Answer 1

Answer:

Step-by-step explanation:

Given  

Factorise the following :x3+8y3+6xy-1

So given x^3 + 8y^3 – 1 + 6xy

We know that a = x, b = 2y, c = - 1

a ^3 + b^3 + c^3 – 3abc = (a + b + c)(a^2 + b^2 + c^2 – ab – bc – ca)

x^3 + (2y)^3 + (-1)^3 – 3(x) (2y) (-1)  

[x + (2y) + (-1) [x^2 + (2y)^2 + (-1)^2 – 2yx – (2y)(-1) – (-1)(x)

(x + 2y – 1) ( x^2 + 4y^2 + 1 – 2xy + 2y + x)