Math, asked by mdadnankne20511, 10 months ago

Factorise the given number (6p-q)^3

Answers

Answered by Mahamnaqve
0

Answer:

Seen all steps available

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Answered by AbbasrMalik
1

Answer:

216 - q³ - 108p²q + 18pq²

Step-by-step explanation:

using the identity ( a - b )³ = a³ - b³ - 3ab(a-b)

a = 6p and -b = -q

(6p - q)³ = (6p)³ - (q)³ +3*6p*-q (6p - q)

             = 216 - q³ - 18pq ( 6p - q)

             = 216 - q³ -  108 p²q + 18 pq²

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