factorise the given question
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3x² + 2y² + z² + 2√6xy + 2√2yz + 2√3xz
= (√3x)² + (√2y)² + (z)² + 2(√3x)(√2y) + 2(√2y)(z) + 2(z)(√3x)
= (√3x + √2y + z)²
= (√3x + √2y + z)(√3x + √2y + z).
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