Question

factorise the polynomial 2x^3+3x^2-11x-6

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:

(x+2)(x+3)(2x+1)

Step-by-step explanation:

By hit and trial 2 is a zero of the polynomialTherefore,

x-2=0

On dividing 2x³+3x²-11x-6 by x-2

We get,

2x³+3x²-11x-2=(x-2)(2x²+7x+3)

On splitting the middle term of 2nd part

We get,

(x-2)(2x+1)(x+3)