factorise the polynomial 2x^3+3x^2-11x-6
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Answer:
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Step-by-step explanation:
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Answer:
(x+2)(x+3)(2x+1)
Step-by-step explanation:
By hit and trial 2 is a zero of the polynomialTherefore,
x-2=0
On dividing 2x³+3x²-11x-6 by x-2
We get,
2x³+3x²-11x-2=(x-2)(2x²+7x+3)
On splitting the middle term of 2nd part
We get,
(x-2)(2x+1)(x+3)
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