Math, asked by ashinikku1693, 9 months ago

factorise the polynomial (a²-b²)³+(b²-c²)³+(c²-a²)³​

Answers

Answered by nitinsengar3
4
(a²-b²)³+(b²-c²)³+(c²-a²)³
We know that
if x + y + z =0 then x^3 + y^3 + z^3 = 3xyz

Here x = a²-b², y = b²-c² and z = c²-a²

a²-b² + b²-c² + c²-a² = 0

Hence
(a²-b²)³+(b²-c²)³+(c²-a²)³ = 3(a²-b²)(b²-c²)(c²-a²)³
= 3(a + b)(a − b)(b + c)(b − c)(c + a)(c − a) = 3(a + b)(b + c)(c + a)(a − b)(b − c)(c − a)

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Answered by harkiratsingh97
3

Answer:

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