factorise the polynomial ax2 + bx2 - ay2 - by2
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Answered by
89
=ax2+bx2-ay2-by2
=x2 (a+b)-y2 (a+b)
=(x2-y2)(a+b)
=(x+y) (x-y)(a+b)
=x2 (a+b)-y2 (a+b)
=(x2-y2)(a+b)
=(x+y) (x-y)(a+b)
Answered by
23
Answer:
ax²+bx²-ay²-by² = (a+b)(x+y)(x-y)
Explanation:
Factorisation of the polyomial
ax²+bx²-ay²-by²
= x²(a+b)-y²(a+b)
= (a+b)(x²-y²)
= (a+b)(x+y)(x-y)
/* By algebraic identity
x²-y² = (x+y)(x-y) */
Therefore,
ax2 + bx2 - ay2 - by2
= (a+b)(x+y)(x-y)
••••
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