Question

factorise the polynomial (x^2-6x)^2-8(x^2-6x+8)-64

Answer 1

ARYAN......PVT.......LTD....

Answer 2

Step-by-step explanation:

=(x^2-6x)^2+0(x^2-6x)-64. 64

let(x^2-6x)=m. /\

=m^2+0m-64. - 32×2

=m^2-8m+8m-64. -16×4

=m×m-8×m+8×m-8×8. -8×8

=m(m-8)+8(m-8)

=(m-8)(m+8)

Re substitute

=(m-8)(m+8)

=(x^2-6x-8)(x^2-6x+8). -8

(x^2-4x-2x-8)(x^2-4x-2x+8). /\

=x(x-4)+2(x-4)x(x-4)-2(x-4). -4 -2

=(x+2)(x-4)(x-2)(x-4). +8

Answer: /\

(x^2-6x)^2-8(x^2-6x+8)-64= -4 -2

(x+2)(x-4)(x-2)(x-4)