Find two numbers whose sum is 27 and product is 182?
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Answered by
1
let one no= x
let second no = y
acc to ques
x+y= 27
x=27-y......(i)
x*y=182.....(ii)
putting value of eq (i) in eq(ii)
(27-y) *y= 182
27y-y*y=182
y*y-27y+182=0
y*y-(14+13)y+182=0
y*y-14y-13y+182=0
y(y-14)-13(y-14)=0
(y-14)(y-13)=0
y-14=0 or y-13=0
y=14 or y=13
if y=14 if y= 13
acc to eq (i) acc to eq(i)
x=27-y x=27-y
=27-14 =27-13
x=13 x=14
let second no = y
acc to ques
x+y= 27
x=27-y......(i)
x*y=182.....(ii)
putting value of eq (i) in eq(ii)
(27-y) *y= 182
27y-y*y=182
y*y-27y+182=0
y*y-(14+13)y+182=0
y*y-14y-13y+182=0
y(y-14)-13(y-14)=0
(y-14)(y-13)=0
y-14=0 or y-13=0
y=14 or y=13
if y=14 if y= 13
acc to eq (i) acc to eq(i)
x=27-y x=27-y
=27-14 =27-13
x=13 x=14
Answered by
5
Let d number be a& b
a+b=27
a=b-27•••••••eq1
a*b=182
Placing d value of eq1
b*(b-27)=182
b^2-27b-182=0
b^2-14b-13b-182=0
(b-14)(b+13)
Therefore,b=14 as the product is positive
And a=13
☺️
a+b=27
a=b-27•••••••eq1
a*b=182
Placing d value of eq1
b*(b-27)=182
b^2-27b-182=0
b^2-14b-13b-182=0
(b-14)(b+13)
Therefore,b=14 as the product is positive
And a=13
☺️
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