Question

factorise the polynomial x^3-4x^2-7x+10 using factor thearom ​

Answer 1

Answer:

1. let x = 1, putting(x-1) in equation

(1)³-4(1)²-7(1)+10=0

1-4-7+10=11 - 11 =0

hence (x-1) is a factor,

now, divide ➗ it, by dividing we get x² - 3x - 10

now by splitting it, we get

x²- 5x + 2x +10

x(x-5)-2(x-5)

(x-2)(x-5)(x-1) are the factors

Step-by-step explanation:

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