Question

factorise the polynomial x^3-6x^2+11x+6

one more question please answer this also Sameer factorise....polynomial : x^3-3x^2-9x-5​

Answer 1

${x}^{3} - 3 {x}^{2} - 9x - 5 \\ ifx = - 1 \\ - 1 - 3 + 9 - 5 = = 0 \\ x + 1 \: is \: a \: factor \\ x + 1) {x}^{3} - 3{x}^{2} - 9x - 5( {x}^{2} - 4x- 5 \\ \: \: \: \: \: \: \: \: \: \: {x}^{3} + {x}^{2} \\ \: \: \: \: \: - - - - - - - - \: \: \: \: \ \: \: \: \: \: \: \: \: \: \: \\ - 4 {x}^{2} - 9x - 5 \\ \: - 4{x}^{2} - 4x \\ - - - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: - 5x - 5 \\ \: \: \: \: \: \: \: \: \: \: \: \: - 5x - 5 \\ - - - - - - - - - \: \: \: \ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: : 0 \\ faotorise \: {x}^{2} - 4x - 5 \\( x - 5)(x + 1) \\ so \: factors \: are \\ (x + 1)(x + 1)(x - 5)$