Math, asked by kkkk65, 1 year ago

factorise the question​

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Answered by Anonymous
3

\mathfrak{\huge{\red{QUESTION}}}

Given

<font color = "blue"><marquee>ANSWER</font color = "blue"></marquee>

 \sqrt{2} {x}^{2}   + 3x +  \sqrt{2}  \\  \\  =  \geqslant  \sqrt{2} {x}^{2}  +2x + x +   \sqrt{2}   \\  \\  =  \geqslant  \sqrt{2} {x}^{2}  +  \sqrt{2}  \times  \sqrt{2} x + x +  \sqrt{2}  \\  \\  =  \geqslant  \sqrt{2} x( x +  \sqrt{2} ) + 1( x  +  \sqrt{2} ) \\  \\  =  \geqslant ( \sqrt{2}x + 1) \: (x +  \sqrt{2} )

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