Factorise the term 4a⁴+81b⁴
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Answer:
4a^2+36a^2b^2+81b^2
Step-by-step explanation:
4a^4+81b^4
((2a)^2+(9b)^2)^2
It is in the form of (a+b)^2
(a+b)^2 = a^2+2ab+b^2
here, a=(2a)^2
b=(9b)^2
=(2a)^2+2(2a)^2(9b)^2+(9b)^2
=4a^2+36a^2b^2+81b^2
I think it helps you..
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