factorise the x^2-4x-5
Answers
Answered by
86
x²-4x-5=0
x²-5x+x-5=0
x(x-5)+1(x-5)
(x-5)(x+1)=0
x=5 or x=-1
Hope it helps..
x²-5x+x-5=0
x(x-5)+1(x-5)
(x-5)(x+1)=0
x=5 or x=-1
Hope it helps..
Answered by
36
given equation is x^2-4x-5
x^2-5x+x-5
x(x-5)+1(x-5)
(x+1)(x-5)
therefore x=-1 or 5
x^2-5x+x-5
x(x-5)+1(x-5)
(x+1)(x-5)
therefore x=-1 or 5
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