Question

factorise these four questions i will give you the brainliest answer

Answer 1

1)-

p² -6p +9

p² -(3+3)p +9

p² -3p -3p +9

p(p-3) -3(p-3)

(p-3)(p-3)

2)-

y²+7y-8

y² -(8-1)y -8

y² -8y +y -8

y(y-8) +1(y-8)

(y+1)(y-8)

3)-

4x²-1

(2x)² -(1)²

(2x+1)(2x-1)

4)-

15a²+12a³

3a²(5 +4a)

(3a²) (5+4a)



I hope this will help you



-by ABHAY

Answer 2

$1. {p}^{2} - 6p + 9 \\ using \: splitting \: the \: middle \: term \\ method \: we \: get \\ {p}^{2} - 3p - 3p + 9 \\ p(p - 3) - 3(p - 3) \\ (p - 3)(p - 3)$


$2. \: \: {y}^{2} + 7y - 8 \\ {y}^{2 } + 8y - y - 8 \\ y(y + 8) - (y + 8) \\ (y - 1)(y + 8)$


$3. \: \: \: 4 {x}^{2} - 1 \\ ( {(2x)}^{2} - {1}^{2} ) \\ using \: identity \: {x}^{2} - {y}^{2} = (x + y)(x - y) \\ we \: get \\ (2x + 1)(2x - 1)$


4. 15a^2+12a^3
taking common 3a^2
we get
3a^2(5+4a)

hope this helps you....