Question

Factorise this:

10a^2-15b^2+20c^2

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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

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We have, $10a² = 2×5×a×a$

$15b² =3×5×b×b$

$and,20c² =2×2×5×c×c$

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The three terms have 5 as a common factor

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$10a² − 15b² + 20c² = (2×5×a×a) − (3×5×b×b) + (2×2×5×c×c)$

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$= 5×(2 × a × a − 3 × b × b + 4 × c × c)$

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$= 5(2a² - 3b² + 4c²)$