Factorise this 9 (a-2)^2-16(a+2)^2
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9 (a-2)^2 -16 (a+2)^2
= { 3 (a-2)} ^2- {4 (a+2)}^2
Now it is in the form of a^2 -b^2 which equals (a+b)(a-b)
={3 (a-2)+ 4 (a+2)}{3 (a-2)- 4 (a+2)}
=(3a -6 + 4a +8)(3a-6 -4a -8)
= (7a+2)(-a -14)
= { 3 (a-2)} ^2- {4 (a+2)}^2
Now it is in the form of a^2 -b^2 which equals (a+b)(a-b)
={3 (a-2)+ 4 (a+2)}{3 (a-2)- 4 (a+2)}
=(3a -6 + 4a +8)(3a-6 -4a -8)
= (7a+2)(-a -14)
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Hope it helps...........................
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