Question

factorise this

a^2 b^4 c^6 - 1 and

36 x^2 - 1/ 169​

Answer 1

Answer:

${a}^{2} {b}^{4} {c}^{6} - 1 \\ \\ (a \: {b}^{2} {c}^{3})^{2} - (1)^{2} \\ \\ (a \: {b}^{2} {c}^{3} - 1)(a \: {b}^{2} {c}^{3} + 1) \\ \\ \\ 36 {x}^{2} - 1 \div 169 \\ \\ ( {6x})^{2} - 1 \div (13)^{2} \\ \\ (6x - 1 \div 13)(6x + 1 \div 13)$