factorise this one also plz
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Q. Factorise 25p² - 36q².
Here,we could see that the both the numbers are perfect square,and they are in the form of a² - b² , so we shall use the identity for a² - b² ,i.e. ( a + b ) ( a - b ).
= 25p² - 36q²
= ( 5p )² - ( 6q )²
= ( 5p + 6q ) ( 5p - 6q ).
Here,we could see that the both the numbers are perfect square,and they are in the form of a² - b² , so we shall use the identity for a² - b² ,i.e. ( a + b ) ( a - b ).
= 25p² - 36q²
= ( 5p )² - ( 6q )²
= ( 5p + 6q ) ( 5p - 6q ).
Anonymous:
Nice answer!
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The question is in the from of a^2-b^2
and a^2-b^2=(a+b)(a-b)
25p^2-36q^2=(a+b)(a-b)
(5p)^2-(6q)^2=(a+b)(a-b)
Where a=5p and b=6q
(5p+6q)(5p-6q)
So, the answer is (5p+6q)(5p-6q)
and a^2-b^2=(a+b)(a-b)
25p^2-36q^2=(a+b)(a-b)
(5p)^2-(6q)^2=(a+b)(a-b)
Where a=5p and b=6q
(5p+6q)(5p-6q)
So, the answer is (5p+6q)(5p-6q)
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