Question

factorise this , please answer quick ​

Answer 1

Answer:

2(x^4-16)

2(x^2+4)(x^2-4)

2(x^2+4)(x+2)(x-2)

Answer 2

Given : 2x4−32

By taking 2 as common 

2x4−32=2(x2−16)

We can further write it as 

2x4−32=2[(x2)2−42]

Based on equation a2−b2=(a+b)(a−b)

We get,

2x4−32=2[(x2+4)(x2−4)]

So we get,

2x4−32=2[(x2−22)(x2+4)]

By using the formula 

2x4−32=2[(x+2)(x−2)(x2+4)]

2x4−32=2(x+2)(x−2)(x2+4)