factorise....this question
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Answered by
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x² + 9√3x + 42
x² + (7√3 + 2√3)x + 42
x² + 7√3x + 2√3x + 42
x(x + 7√3) + 2√3(x + 7√3)
(x + 7√3)(x + 2√3)
![. .](https://tex.z-dn.net/?f=.)
x² + (7√3 + 2√3)x + 42
x² + 7√3x + 2√3x + 42
x(x + 7√3) + 2√3(x + 7√3)
(x + 7√3)(x + 2√3)
Answered by
3
Hello friends Hello friends!!
Here is your answer :
![{x}^{2} + 9 \sqrt{3} x + 42 {x}^{2} + 9 \sqrt{3} x + 42](https://tex.z-dn.net/?f=+%7Bx%7D%5E%7B2%7D++%2B+9+%5Csqrt%7B3%7D+x+%2B+42)
![= > {x}^{2} + 7 \sqrt{3} x + 2 \sqrt{3} x + 42 = > {x}^{2} + 7 \sqrt{3} x + 2 \sqrt{3} x + 42](https://tex.z-dn.net/?f=+%3D++%26gt%3B++%7Bx%7D%5E%7B2%7D++%2B+7+%5Csqrt%7B3%7D+x+%2B+2+%5Csqrt%7B3%7D+x+%2B+42)
![x(x + 7\sqrt{3} ) + 2 \sqrt{3} (x + 7 \sqrt{3} ) x(x + 7\sqrt{3} ) + 2 \sqrt{3} (x + 7 \sqrt{3} )](https://tex.z-dn.net/?f=x%28x+%2B++7%5Csqrt%7B3%7D+%29+%2B+2+%5Csqrt%7B3%7D+%28x+%2B+7+%5Csqrt%7B3%7D+%29)
![(x + 7 \sqrt{3} )(x + 2 \sqrt{3} ) (x + 7 \sqrt{3} )(x + 2 \sqrt{3} )](https://tex.z-dn.net/?f=%28x+%2B+7+%5Csqrt%7B3%7D+%29%28x+%2B+2+%5Csqrt%7B3%7D+%29)
Hope it helps you.. ^_^
#Be Brainly
Here is your answer :
Hope it helps you.. ^_^
#Be Brainly
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