Question

factorise this question please

Answer 1

I hope it helps u,if it is correct :)

Answer 2

b)  x3 + 13x2 + 32x + 20 Let p(x) = x3 + 13x2 + 32x + 20 Put x = –1 in p(x), we get p(–1) = (–1)3 + 13(–1)2 + 32(–1) + 20          = (–1) + 13 + (–32) + 20         = 33 – 33 = 0 Hence (x + 1) is a factor of p(x) Now divide p(x) with (x + 1), we get x2 + 12x + 20 ∴ p(x) = (x + 1)(x2 + 12x + 20) Let's factorize x2 + 12x + 20 ⇒ p(x) = (x + 1)(x2 + 10x + 2x + 20)            = (x + 1)[x(x + 10) + 2(x + 10)]            = (x + 1)(x + 10)(x + 2).....
plz..solve this in this way..