Question

Factorise this question please
x²-21x+108

Answer 1

Answer:

The answer is $(x-12)(x-9)$

Step-by-step explanation:

Given expression is

  $x^2-21x+108$

Split the middle term

 $=x^2-12x-9x+108$

Group the terms

$=(x^2-12x)+(-9x+108)$

Factor each terms

 $=x(x-12)-9(x-12)$

Take out common factor

  $=(x-12)(x-9)$

Answer 2

Answer:

x²-21x+108

x²-9x-12x+108

x(x-9)-12(x-9)

(x-9)(x-12)