Math, asked by prachiibodele8, 21 days ago

in triangle abc, ab=be. circle through ab intersects ae & be at b&c prove that dc || ab.

Ans:- Step by step solution

We are given,

AE = BE

,<br>

:. /_EAB = /_EBA->(1)

<br> Also, we know, exterior angle of a cyclic quadrilateral is equal to opposite interior angle.<br>

:. /_EBA = /_EDC->(2)

<br> From (1) and (2),<br>

/_EAB = /_EDC

<br> As both these angles are equal, it implies

DC

and

AB

are parallel to each other.<br>​

Attachments:

Answers

Answered by alamshahil819
1

Answer:

We are given,

AE = BE

,<br>

:. /_EAB = /_EBA->(1)

<br> Also, we know, exterior angle of a cyclic quadrilateral is equal to opposite interior angle.<br>

:. /_EBA = /_EDC->(2)

<br> From (1) and (2),<br>

/_EAB = /_EDC

<br> As both these angles are equal, it implies

DC

and

AB

are parallel to each other.<br>

Answered by Jiya0071
2

Refer the above attachment

Attachments:
Similar questions