in triangle abc, ab=be. circle through ab intersects ae & be at b&c prove that dc || ab.
Ans:- Step by step solution
We are given,
AE = BE
,<br>
:. /_EAB = /_EBA->(1)
<br> Also, we know, exterior angle of a cyclic quadrilateral is equal to opposite interior angle.<br>
:. /_EBA = /_EDC->(2)
<br> From (1) and (2),<br>
/_EAB = /_EDC
<br> As both these angles are equal, it implies
DC
and
AB
are parallel to each other.<br>
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Answer:
We are given,
AE = BE
,<br>
:. /_EAB = /_EBA->(1)
<br> Also, we know, exterior angle of a cyclic quadrilateral is equal to opposite interior angle.<br>
:. /_EBA = /_EDC->(2)
<br> From (1) and (2),<br>
/_EAB = /_EDC
<br> As both these angles are equal, it implies
DC
and
AB
are parallel to each other.<br>
Answered by
2
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