Math, asked by Shivsm, 1 year ago

Factorise this : x^8 - y^8


xyz162: x^8-y^8=(x^4)^2-(y^4)^2=(x^4+y^4)(x^4-y^4)=(x^4+y^4){(x^2)^2-(y^2)^2}=(x^4+y^4){(x^2+y^2)(x^2-y^2)}=(x^4+y^4){(x^2+y^2)(x+y)(x-y)

Answers

Answered by gaurav2013c
40
x^8 - y^8

=> (x^4)^2 - (y^4)^2

=> ( x^4 - y^4) (x^4 + y^4)

=> [ (x^2)^2 - (y^2)^2] (x^4 + y^4)

=> (x^2 - y^2) ( x^2 +y^2) (x^4 + y^4)

=> (x-y) (x+y) (x^2 +y^2) (x^4 + y^4)
Answered by BloomingBud
27

Hi \:  \:   !!! \\  \\ <br /><br />Here  \:  \: is  \:  \: your \:  \:  answer,  \\  \\ <br /><br />Factorise   \:  \:  \: {x}^{8}  -  {y}^{8}  \\   \\  {( {x}^{4} )}^{2}  -  {( {y}^{4} )}^{2}  \\ \\  ( {x}^{4}  +  {y}^{4} )( {x}^{4}  -  {y}^{4} ) \\  \\ ( {x}^{4}  +  {y}^{4} )( {( {x}^{2} )}^{2}  -  { ({y}^{2} )}^{2} ) \\  \\ ( {x}^{4}  +  {y}^{4} )( {x}^{2}  +  {y}^{2} )( {x}^{2}  -  {y}^{2} ) \\  \\ ( {x}^{4}  +  {y}^{4} )( {x}^{2}  +  {y}^{2} )( {( {x}^{2}) }^{2}  -  {(y)}^{2}  ) \\  \\ ( {x}^{4}  +  {y}^{4} )( {x}^{2}  +  {y}^{2} )( x-  y )(x - y) \\  \\  \\ Hope \:  \: it \:  \: helps.
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