Question

factorise using factor theorem y^3 - 7 x + 6​

Answer 1

Answer:

Step-by-step explanation:

$y^3-7y+6=(y^3-y^2)+(y^2-7y+6)$

Factorising each bracket, we have

$=y^3-7y+6\\\\=(y^3-y^2)+(y^2-7y+6)\\=y^2(y-1)+(y-1)(y-6)\\=(y-1)(y^2+y-6)\\=(y-1)(y-2)(y+3)$