Question

factorise using identies
(4а + 7b)square- (За + 8b)square​

Answer 1

Answer:

$\tt \: ((4a + 7b) + (3a + 8b))((4a + 7b) - (3a + 8b))$

Step-by-step explanation:

$\tt {(4a + 7b)}^{2} - {(3a + 8b)}^{2} \\ \\ \tt \: using \: \: \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: formula... \\ \\ \tt \: ((4a + 7b) + (3a + 8b))((4a + 7b) - (3a + 8b))$