Question

factorise using identity 16xsquare-25​

Answer 1

Given equation,

$16x^{2} -25=0$

$\boxed{\bold{Formula \ to \ be \ used = a^{2} -b^{2} =(a+b)(a-b)}}}}$

Now,

$\sqrt{16x^{2} } = 4x\\\\\ \sqrt{25} =5$

$\boxed{\boxed{\bold{Therefore, the \ factorized \ expression \ is \ (4x+5)(4x-5)}}}$

                                                         

Answer 2

Indentity =>

${a}^{2} - {b}^{2} = (a + b)(a - b)$

$= > 16 {x}^{2} - 25 \\ \\ = > {4x}^{2} - {5}^{2} \\ \\ = > (2x + 5)(2x - 5)$