Question

factorise using identity 27x3 + 125y3

Answer 1

hey here is ur answer
______________________________
27x³+125y³=(3x)³+(5y)³
so
by using formula
x³+y³=(x+y)(x²-xy+y²)

(3x+5y)(9x²-15xy+25y²)

hope dis help

Answer 2

27x³ + 125y³ = (3x + 5y)(9x² - 15xy + 25y²)

Given :

The expression 27x³ + 125y³

To find :

To factorise using identity

Identity Used :

a³ + b³ = (a + b)(a² - ab + b²)

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

27x³ + 125y³

Step 2 of 2 :

Factorise the expression

We use the identity

a³ + b³ = (a + b)(a² - ab + b²)

Thus we get

$\sf 27 {x}^{3} + 125 {y}^{3}$

$\sf = {(3x)}^{3} + {(5y)}^{3}$

$\sf =(3x + 5y) \bigg[ {(3x)}^{2} - 3x.5y + {(5y)}^{2} \bigg]$

$\sf =(3x + 5y) (9 {x}^{2} - 15xy + 25 {y}^{2} )$

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Answer 3

Given:

An algebraic expression 27x³ + 125y³.

To Find:

The factorized form of the given expression is?

Solution:

The given problem can be solved using standard algebra expansions.

1. The given expression is 27x³ + 125y³.

2. The expression x³ -y³ can be written as

• (x³ + y³) = ( x + y )( x² - x y + y² ).

3. Use the above formula to expand the given expression.

=> 27x³ + 125y³ = 3³x³ + 5³y³,

=> 3³x³ + 5³y³ = (3x+5y)(9x² - 3x * 5y + 25y²),

=> 3³x³ + 5³y³ = (3x+5y)(9x² - 15x y + 25y²),

4. The expansion of 27x³ + 125y³ is (3x+5y)(9x² - 15x y + 25y²).

Therefore, the factorization of 27x³ + 125y³ is (3x+5y)(9x² - 15x y + 25y²).