Math, asked by mundhramuskan3, 7 months ago

Factorise using identity
x - y -  {x}^{2}  +  {y}^{2}

Answers

Answered by Cynefin
7

 \LARGE{ \underline{ \green{ \sf{Required \: answer:}}}}

We have to factorise:

  • x - y - x² + y²

Let's factorise by using identity within the terms to get the simplified value of the given polynomial. It can written as:

⇛ x - y - (x² - y²)

Here, we can use the identity of x² - y² = (x + y)(x - y),

⇛ (x - y) - (x + y)(x - y)

In the both sides of the '-' minus signs, (x - y) is common. So, we take it common to factorise more.

⇛ (x - y){1 - (x + y)}

This is equals to,

⇛ (x - y)(1 - x - y)

And we are done factorising the above polynomial...(Ans - (x - y)(1 - x - y)

Answered by Anonymous
2

\LARGE{ \underline{ \underline{ \bf{ \purple{Required \: Answer:}}}}}

We have to factorise:

x - y - x² + y²

Let's factorise by using identity within the terms to get the simplified value of the given polynomial. It can written as:

⇛ x - y - (x² - y²)

Here, we can use the identity of x² - y² = (x + y)(x - y),

⇛ (x - y) - (x + y)(x - y)

In the both sides of the '-' minus signs, (x - y) is common. So, we take it common to factorise more.

⇛ (x - y){1 - (x + y)}

This is equals to,

⇛ (x - y)(1 - x - y)

And we are done factorising the above polynomial...(Ans - (x - y)(1 - x - y)

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