Question

factorise using splitting the middle term √3x2 + 4x + √3

Answer 1

Answer:

$( \sqrt{3} x + 1)(x + \sqrt{3} )$

Step-by-step explanation:

Given expression :

$\sqrt{3} {x}^{2} + 4x \: + \sqrt{3}$

Here,

$\sqrt{3} \: \times \sqrt{3} = 3 \: \: \: and \: \: 4 = 3 \: + 1$

Therefore,

$\sqrt{3} {x}^{2} + 3x \: + x \: + \sqrt{3}$

$\sqrt{3} {x}^{2} + \sqrt{3} \times \sqrt{3} x \: + x + √3$

$\sqrt{3} x(x + \sqrt{3} ) + 1(x + \sqrt{3} )$

$( \sqrt{3} x + 1)(x + \sqrt{3} )$

Hence, the factorisation.

Answer 2

(｡◕‿◕｡)

Answer

☞ √3x^2 + 4x + √3

☞ √3x^2 + 3x + x + √3

☞ √3x^2 + √3√3x + x + √3

☞ √3 (x + √3) + 1 (x + √3)

☞ (x + √3)(√3x + 1)