Question

factorise using suitable groupings the 4x²+2y²+x²y²+8

Answer 1

${4x}^{2} + 2 {y}^{2} + {x}^{2} {y}^{2} + 8 \\ = 4 {x}^{2} + 8 + 2 {y}^{2} + {x}^{2} {y}^{2} \\ = 4( {x}^{2} + 2) + {y}^{2} (2 + {x}^{2}) \\ = ( {x}^{2} + 2)(4 + {y}^{2})$

Answer 2

Answer:

Follow the above answer dear