Question

factorise using trinomial factorisation 1-8a^3 ​

Answer 1

1 – 8a³

= (1)³ – (2a)³

Using Identity : x³ – y³ = (x – y)(x² + xy + y²)

Here, x = 1 and y = 2a

So, 1 – 8a³ = (1)³ – (2a)³

= (1 – 2a) {(1)² + (1 × 2a) + (2a)²}

= (1 – 2a) (1 + 2a + 4a²)

Answer : 1 – 8a³ = (1 – 2a) (1 + 2a + 4a²)

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Answer 2

Answer:

1 – 8a³

= (1)³ – (2a)³

Using Identity : x³ – y³ = (x – y)(x² + xy + y²)

Here, x = 1 and y = 2a

So, 1 – 8a³ = (1)³ – (2a)³

= (1 – 2a) {(1)² + (1 × 2a) + (2a)²}

= (1 – 2a) (1 + 2a + 4a²)