Question

factorise vvvvvvvvvvv​

Answer 1

Step-by-step explanation:

${10a}^{2} - {15b}^{2} + {20c}^{2} \\ {10a}^{2} = 2 \times 5 \times a \times a = 5(2 \times a \times a) \\ {15b}^{2} = 5 \times 3 \times b \times b = 5(3 \times b \times b) \\ {20c}^{2} = 2 \times 2 \times c \times c \times 5 = 5(2 \times 2 \times c \times c) \\ = 5( {2a}^{2} + {3b}^{2} \times {4c}^{2} )$

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