Question

factorise: (x+1)^2 + 5(x+1) -14​

Answer 1

hope it's helps....... ♥

Answer 2

$(x + 1) ^{2} + 5(x + 1) - 14$

$({x}^{2} + {1}^{2} +2 \times x \times 1) + (5x + 5) - 14$

${x}^{2} + 5x + 1 + 5 - 14$

${x}^{2} + 5x - 8$

$\huge\mathfrak{iTzSweetStar}$♡