Factorise: (x+1)^3 - (x-1)^3
Answers
Answered by
160
Hey dear!
Here is yr answer.....
=> (x+1)³ - (x-1)³
[ (a+b)³ = a³+3a²b+3ab²+b³ ]
[ (a-b)³ = a³-3a²b+3ab²-b³ ]
=> [ x³+3(x)²(1)+3(x)(1)²+(1)³ ] - [ x³-3(x)²(1)+3(x)(1)²-(1)³]
=> x³+3x²+3x+1 - x³+3x²-3x+1
=> 6x²+2
=> 2(3x²+1)
Hope it hlpz...
Here is yr answer.....
=> (x+1)³ - (x-1)³
[ (a+b)³ = a³+3a²b+3ab²+b³ ]
[ (a-b)³ = a³-3a²b+3ab²-b³ ]
=> [ x³+3(x)²(1)+3(x)(1)²+(1)³ ] - [ x³-3(x)²(1)+3(x)(1)²-(1)³]
=> x³+3x²+3x+1 - x³+3x²-3x+1
=> 6x²+2
=> 2(3x²+1)
Hope it hlpz...
Answered by
54
(x+1-x+1)[(x+1)^2+(x-1)^2+(x+1)(x-1)
2[(x^2+1+2x)+(x^2+1-2x)+x^2-1
2[x^2+1+2x+x^2+1-2x+x^2-1]
2(3x^2+1)
6x^2+2
is your answer
2[(x^2+1+2x)+(x^2+1-2x)+x^2-1
2[x^2+1+2x+x^2+1-2x+x^2-1]
2(3x^2+1)
6x^2+2
is your answer
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