Math, asked by raven3, 1 year ago

factorise (x+1)(x+2)(x+3)(x+4) - 3

Answers

Answered by Robin0071
1
Solution:-

given by:-

(x + 1)(x + 2)(x + 3)(x + 4) - 3 \\ ( {x}^{2}  +  5x + 4)( {x}^{2}  + 5x + 6) - 3 \\ (  {x}^{4}  + 5 {x}^{3}  + 6 {x}^{2}   + 5 {x}^{3}  + 25 {x}^{2}  + 30x + 4 {x}^{2}  + 20x + 24 - 3)  \\  {x}^{4}  + 10 {x}^{3}  + 33 {x}^{2}  + 50x + 21)ans

raven3: this can be factorised further by middle term break
Answered by divyanshi1252
1

Answer:

x^4+10x^3+35x^2+50x+21

Step-by-step explanation:

(x+1)(x+2)(x+3)(x+4)-3

= [(x+1)(x+2)][(x+3)(x+4)]-3

= (x^2+2x+x+2)(x^2+4x+3x+12)-3

= (x^2+3x+2)(x^2+7x+12)-3

= (x^4+7x^3+12x^2+3x^3+21x^2+36x+2x^2+14x+24)-3

= (x^4+10x^3+35x^2+50x+24)-3

= x^4+10x^3+35x^2+50x+24-3

= x^4+10x^3+35x^2+50x+21

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