factorise (x+1)(x+2)(x+3)(x+4) - 3
Answers
Answered by
1
Solution:-
given by:-

given by:-
raven3:
this can be factorised further by middle term break
Answered by
1
Answer:
x^4+10x^3+35x^2+50x+21
Step-by-step explanation:
(x+1)(x+2)(x+3)(x+4)-3
= [(x+1)(x+2)][(x+3)(x+4)]-3
= (x^2+2x+x+2)(x^2+4x+3x+12)-3
= (x^2+3x+2)(x^2+7x+12)-3
= (x^4+7x^3+12x^2+3x^3+21x^2+36x+2x^2+14x+24)-3
= (x^4+10x^3+35x^2+50x+24)-3
= x^4+10x^3+35x^2+50x+24-3
= x^4+10x^3+35x^2+50x+21
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